Knowledge is to share

WIN XP : FCKGW-RHQQ2-YXRKT-8TG6W-2B7Q8 SP1 : MYHVT-WQ4GM-QRPVF-V86FC-P3R8Y SP2 : MBG8X-MMZK7-VWM8D-KFG96-9C4MY    OR   YQ7XW-QPT6C-233QF-RRXV7-VF7TY   OR  DYMRC-TM3K2-KXHR7-FP8DV-MC6X3 SP3 : QDWAX-3XQ7W-F68F4-HYQ36-DXR7W

Now when click on a link, it opens a popup window, which contain a data entry form, I entered some information into that form. Then I need to review other information, from other popup window, so I go back to the main window, click on another link, a new popup window get open which contain the information I need to review. I get the information and close this popup window, so now I am on the main window, then again I click on the link for that data entry form, so the popup window comes up but I lost the information that I have entered, that's because I am relodiing the popup window once again. Let us see how it works, When attempt to open the window again with the same name in the second parameter of the windows open method, you will to get the windows handle. If the window is already open, it will return the handle of the opened window or it will open a new window and return it's handle The first parameter (the url) is passed as an empty strin